(x^2+2)(2x^2+5x-1)=

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Solution for (x^2+2)(2x^2+5x-1)= equation:


Simplifying
(x2 + 2)(2x2 + 5x + -1) = 0

Reorder the terms:
(2 + x2)(2x2 + 5x + -1) = 0

Reorder the terms:
(2 + x2)(-1 + 5x + 2x2) = 0

Multiply (2 + x2) * (-1 + 5x + 2x2)
(2(-1 + 5x + 2x2) + x2(-1 + 5x + 2x2)) = 0
((-1 * 2 + 5x * 2 + 2x2 * 2) + x2(-1 + 5x + 2x2)) = 0
((-2 + 10x + 4x2) + x2(-1 + 5x + 2x2)) = 0
(-2 + 10x + 4x2 + (-1 * x2 + 5x * x2 + 2x2 * x2)) = 0
(-2 + 10x + 4x2 + (-1x2 + 5x3 + 2x4)) = 0

Combine like terms: 4x2 + -1x2 = 3x2
(-2 + 10x + 3x2 + 5x3 + 2x4) = 0

Solving
-2 + 10x + 3x2 + 5x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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